First of all there must be a temperature gradient amongst the two surfaces to acts as the driving force for thermal flux to take place.
Assume we have air on both sides of the wall.
You know that air temperature on top side is 57 °F. You should know air temperature on the other side.
Then……
Q1 = htc1 * (Ti – Twi)
Q2 = k/s * (Twe – Twi)
Q1 = htc2 * (Te – Twe)
Where:
htc1 = convection heat transfer coefficient at film temperature (top side)
htc2 = convection heat transfer coefficient at film temperature (bottom side)
k = light weight concrete wall thermal conductivity
s = light weight concrete wall thickness
Ti = air temperature (top side)
Te = air temperature (bottom side)
Twi = wall temperature (top side)
Twe = wall temperature (bottom side)
Choose a trial temperature Twi, compute htc1 (trial), put Q1 = Q2 and compute Twe (trial)
Then you put Q2 = Q3 and solve for htc2 and check whether it matches the value of htc2 you have separately calculated for the relevant geometry and with Te and Twe (trial). Iterate until results converge.
You may find of some help this calculator:
One last note (to be more precise you should include also the radiation heat transfer component)