At 180 to 219, you have a 40 degree approach, compared to an 80 degree approach when you started at 140. The basics of heat transfer given simplisticlly as TTT, Time, Temperature, and Turbulence. Heat transfer rates are a function of the driving force (delta T) and the turbulence not only in the vessel caused by your stirrer, but in the jacket as well, and the time of contact, your overall heat transfer rate for this type equipment may have approached equilibrium.
The factor of time is not in play here as I see it.
And, remember, what is in the kettle is losing heat to the surrounds at the surface by the same processes.
Therefore anything you can do to have an effect on the temperature of the glycol, (probably not very doable, or you would have done it) or the turbulence in the vessel or the jacket will help you over the hump. That might involve stirrer speeds, and/or pump rates for the glycol.
Plus, do you actually need 50/50 water/glycol. As pointed out by the poster above, water glycol mixtures are not as good a heat transfer agent as pure water. True pure water has the highest specific heat, but the automotive world has to accept and design around the limitations of antifreeze mixtures so that we can park our cars outside in the wintertime. (A problem ignored in the temperate climates.)
If you have no freeze problems with your coolant, why not reduce the ratio of glycol to water. The specific heat of the fluid increases as you go towards pure water. Undoubtedly you are using a mixture for some reason, probably a combination of freeze protection and corrosion protection. Investigate changing the mixture.
Now, addressing your configuration. When you say made incorrectly, not dimpled, with a secondary jacket that is dimpled above it?? Does above it mean outside it?? Is the dimple plate clamped over the original non-dimpled jacket? Is the original jacket integral, or clamped on? Did you use heat transfer mastic between any clamped jacket to the surface to which you want to transfer heat?
And then, as I understand your explaination, you flow your hot water/gyclol mixture first into the original jacket, at the top, and then to the secondary. If this is understood correctly, the hot fluid in the original jacket will transfer heat both ways. It will transfer some heat into the kettle, and cool off in the process, and then as it flows through the secondary jacket, it will pick up some heat from the primary jacket, reheating itself, (at the kettle's expense) until you see the inlet and outlet temperatues being equal as you state.
You have to pipe this so that your heat is always flowing form the hottest to the coldest. Right now you have a competition between where the coldest is for the heat in the primary jacket to flow to. When the oil is cool, the kettle wins. When the oil is warmer, the secondary jacket wins. Early in the process, the secondary jacket is acting like a heated insulation blanket. The heat flows more easily to the oil, and your transfer rate is good to the oil. Later, the oil is hot, and the heat would rather flow back into the secondary jacket, with it's superior HTC than the oil in the kettle. What little heat that is going into the kettle is being lost to the atmosphere at the top.
That is just the way I see it.
rmw