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Heat of dilution

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Adamsdr3

Chemical
Joined
May 4, 2015
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I have a semi-simple question. I need the heat of dilution for H2SO4 from 80 to 25%. I have a table here:​


To get the heat generated, I need to integrate the function for the curve from 80 to 25 and then multiply the number of lbs of H2SO 4 I have, correct?​
 
Adamsdr3
What you need to do is read the value from the chart at 25% (312) and then subtract the value at 80% (150) So then the heat released per lb H2SO4 is 162 BTU/Lb H2SO4.
Don't forget that your starting material is only 80% H2SO4 when you multiply it out to try to get the total BTU's released.

Regards
StoneCold
 
Integrating for the area under the curve would have worked if the x axis was the heat of dilution for a fixed 1 lb of H2SO4 in solution - this is not what we have on the x-axis.
 
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