Heat of dilution

[Adamsdr3]

I have a semi-simple question. I need the heat of dilution for H2SO4 from 80 to 25%. I have a table here:​

http://www.generalchemical.com/assets/pdf/Sulfuric_Acid_Water_Heat_of_Dilution_13.pdf

To get the heat generated, I need to integrate the function for the curve from 80 to 25 and then multiply the number of lbs of H2SO 4 I have, correct?​

 

[StoneCold]

Adamsdr3
What you need to do is read the value from the chart at 25% (312) and then subtract the value at 80% (150) So then the heat released per lb H2SO4 is 162 BTU/Lb H2SO4.
Don't forget that your starting material is only 80% H2SO4 when you multiply it out to try to get the total BTU's released.

Regards
StoneCold

 

[georgeverghese]

Integrating for the area under the curve would have worked if the x axis was the heat of dilution for a fixed 1 lb of H2SO4 in solution - this is not what we have on the x-axis.