If you cannot find them, these can be estimated as the sum of the standard heats of formation of SO
2, H
2O, CO
2 resulting from stoichiometric combustion with oxygen plus the (negative) standard heat of formation of the chemical itself.
An example for dimethylsulfide considering water is condensed back as a liquid at 25 deg C and all other gases are returned to 25 deg C (standard state):
C2H6S + 4.5 O2 => 2 CO2 + 3 H2O + SO2
The heat of combustion and standard heats of formation are given in kJ/mol.
carbon dioxide: 2[×]393.51 = 787.02
water: 6[×]142.915 = 857.49
sulfur dioxide: 1[×]296.8 = 296.80
dimethyl sulfide: -37.40
total heat of combustion, 1903.91
Similarly for hydrogen sulfide and methyl mercaptan.
Then, multiply the heats of combustion by their vol%, and add the results. Kindly check my calculations.
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