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H2 Cylinder

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madhavank007

Chemical
Jun 12, 2003
7
Dear Friends
Wish u very happy new year
i got one ?

i am using H2 Cylinder 51 inch height 9 inch dia pressure 125 kg/cm2 g

i am using hydrogen for my process
at 50 kg/cm2 i stopped the hydrogen.
is it possible to calc the remaining hydrogen amount with this data.
i don't know the cylinder weight
i know only initial amount,pressure and final pressure
can u able to help me


K Madhavan
 
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From thermodynamic tables obtain the specific volume (m3/kg) at the starting P, T conditions. From the original known mass M1, kg, of gas you estimate the volume, m3 of the cylinder. For example, at 25oC and the indicated pressure the specific volume would be, if I'm not wrong, 0.10715 m3/kg.

Then V, volume of the cylinder = M1 x 0.10715.

Thermodynamic tables would also tell you the specific volume of hydrogen at the final P, T conditions. At 25oC and the indicated pressure, it would be 0.25364 m3/kg.

Having estimated the volume V of the bottle before, you could now estimate the mass of hydrogen left in the bottle dividing the V by 0.25364.

If the assumed temperatures and the readings I took from the NIST tables are OK, the reduction in mass would be:

100*[1-(0.10715/0.25364)] = 57.755%​

A Happy New Year. [smile]
 
About 0.5 pound

PV = nRT
n = PV/RT
P = 50 kg/cm2 g = 711 lb/in2 g = 726 psia
V = 3.1415 x (4.5/12)^2 x (51/12) = 1.88 ft3
T = ?, so assume 60 F = 520 R
n = 726 x 1.88 / (10.73 x 520) = 0.247 lb-mols
m = n x MW = 0.247 x 2.01594 = 0.49 lb



Good luck,
Latexman
 
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