A514
Mechanical
- Feb 16, 2007
- 8
I am running a system that incorporates a 1.50 H.P. A.C. motor running at 1160 RPM's This is directly coupled into an electric clutch that runs upto 24 v.dc. and that generates up to 36 ft-lbs of torque at 24 volts and can be adjusted downward. From the output of the clutch is a 12 tooth sprocket running a drive chain into a 21 tooth sprocket. Where the 21 tooth sprocket is mounted is a line shaft that runs into 2) Cone-Drive model 30 gear reducers that are 60:1 ratio's. The output shaft changes direction and a pinion gear is mounted vertically. The pinion gear is a 4.00" P.D. that drives one set of gear racks and pulls a set of arms. Each set of arms weights about 800 pounds that slides into the frame.The RPM's of this shaft is around 11RPM's. I ran my calculations and I figured I only needed 3/8 horsepower motor based on a 0.3 coefficient of friction. The arms travel inward or outward until they hit a hard stop at that point the electric clutch slips. The clutch starts out at high voltage and drops down to about 12 volts when running. The problem is when after the arms hit the stop the motor stalls and I can't cause the arms to change directions.It's like I need more torque to break the arms free. It's almost like the gear box locks up and I need even more torque to drive the arms in or out. I was wondering how much break away torque I need to reverse directions with theis 60:1 ratio gear box? Also would lowering the ratio reduce the breakaway torque into the gearbox? Thanks in advance.