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formula transposition

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bladeblaster

Mechanical
Oct 5, 2006
10
Hi I am trying to transpose this temperature rise formula to find current. Current = J. I have tried but am not 100% confident so please could someone check if I am right. Cheers Terry.

[Δ]T=J[²]L[²]
2ykA[²]

To make J the subject I have got

Sqroot ([Δ]T)2ykA[²]=J
L[²]

It's been a long time since I have transposed a formula of this complexity, any advice well recieved.

Many thanks.
 
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First you multiplied both sides by 2ykA^2;
Then you divided both sides by L^2;
Then you took the square root of both sides.

Looks right to me.

debodine
 
Looks essentially correct. I would only add that, when you take the square root of both sides, there is both a positive and a negative solution. I suppose this means that it doesn't matter which direction the current is flowing in terms of causing a specified temperature rise.
 
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