DiplingAndre
Petroleum
- Nov 19, 2008
- 29
Hello,
I've some problems withe the calculation Fig. 4 in API 5LC
The Formula is A = (1,15(D-2t)/(e-D/t-2e-1))-t
D is for example 16" or 406,4 mm
t = 0,204" or 5,2 mm
e = 0,1025" or 102,5 mm
I think that the formula is not correct coz i found in an old version (1991) A = (1,15(D-2t)/(e*D/t-2e-1))-t
But when I try to calculate i don't get realistic results.
What am i doing wrong?
I've some problems withe the calculation Fig. 4 in API 5LC
The Formula is A = (1,15(D-2t)/(e-D/t-2e-1))-t
D is for example 16" or 406,4 mm
t = 0,204" or 5,2 mm
e = 0,1025" or 102,5 mm
I think that the formula is not correct coz i found in an old version (1991) A = (1,15(D-2t)/(e*D/t-2e-1))-t
But when I try to calculate i don't get realistic results.
What am i doing wrong?