bastolos
Mechanical
- Jul 10, 2002
- 11
We are going to do a Hard Hat safety demonstration next week and someone send us a outline on what to do, but it isn't making sense to me. The demonstration is dropping a 3.5 ounce washer 32 ft onto a balloon (filled with water) wearing a hard hat and one wearing a ball cap. The one with the ball cap should break. But they say to back this up with calculations.
They say: The force of a falling object can be calculated approx. by multiplying the weight of the object by the distance it falls. A 3.5oz washer falling 32ft will generate a force of 7ft-lbs of impact. Should this washer strike an unprotected head, the force of the blow would be equivalent to 560lbs; when a hard hat is worn, the force transmitted to the neck and spine is reduced to only 127lbs.
How to they come up with the 560lbs? I don't know if they mean 560lbs per a square unit of measure or what. There's no way dropping that washer that far will be equivalent to 560 lbs, it just doesn't make any sense. Can anyone make sense of this and lend a hand. I would appreciate it. This study came from PSU.
They say: The force of a falling object can be calculated approx. by multiplying the weight of the object by the distance it falls. A 3.5oz washer falling 32ft will generate a force of 7ft-lbs of impact. Should this washer strike an unprotected head, the force of the blow would be equivalent to 560lbs; when a hard hat is worn, the force transmitted to the neck and spine is reduced to only 127lbs.
How to they come up with the 560lbs? I don't know if they mean 560lbs per a square unit of measure or what. There's no way dropping that washer that far will be equivalent to 560 lbs, it just doesn't make any sense. Can anyone make sense of this and lend a hand. I would appreciate it. This study came from PSU.