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CW3

Mechanical
Nov 19, 2003
51
I need some confirmation or correction on an issue. I have a container of 2.75% (w/v) Calcium Chloride. Can I say that this is a 0.25M solution? Given the molecular weight of CaCl2 is 110.98g, is this a correct statement?

Thanks,

CW3
 
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Not sure what you mean by w/v, or if the container is a water solution?

Do you mean 2.75% by weight of CaCl2 in water (solution)? I.e. 2.75 g of salt in 100 g of solution.

Then yes, I calculate .25M concentration too.
 
Yes, but if you want mention solution in w/v (weight to volume) you should mention units too: w/v gr/ml
w/v by itself is not clear.
 
Yes, (w/v) is weight to volume (g/mL). Thanks.I am titrating di-ammonium EDTA with the calcium chloride to determine % available pure EDTA and just needed to be sure of the molarity of the calcium chloride I had on hand.

You guys' input is very much appreciated, thanks.

CW3
 
Be sure you are using the anhydrous (hygroscopic) salt. Otherwise, the commercial salt frequently available is the dihydrate MW: 147.01. In which case the resulting molar concentration may be lower.
 
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