KirbyWan
Aerospace
- Apr 18, 2008
- 586
Howdy all,
So I'm designing a test stand for an electric motor. It wants a flywheel to resist the motor acceleration. Here is the flywheel the CMM (component maintenance manaual) wants:
Inertia flywheel, 0.9 Nm2 (2.15 lbf ft2), 0 to 10000 RPM.
Now, I'm confused, because I thought the units of inertia were Kg*m^2. That is Kilograms meters squared (MLL), not N*m^2 or Newton meters squared (MLLL/SS).
Based on the conversion, I expect they meant a flywheel of .092 Kg*M^2 which would be equivalent to .2 * (3.28^2) lb-ft^2.
But I've never designed a flywheel before and thought I might have missed a lesson a couple decades ago.
Can anyone give me a sanity check? Did they just put the wrong units calculating the weight instead of using the mass?
Thanks all,
-Kirby
Kirby Wilkerson
Remember, first define the problem, then solve it.
So I'm designing a test stand for an electric motor. It wants a flywheel to resist the motor acceleration. Here is the flywheel the CMM (component maintenance manaual) wants:
Inertia flywheel, 0.9 Nm2 (2.15 lbf ft2), 0 to 10000 RPM.
Now, I'm confused, because I thought the units of inertia were Kg*m^2. That is Kilograms meters squared (MLL), not N*m^2 or Newton meters squared (MLLL/SS).
Based on the conversion, I expect they meant a flywheel of .092 Kg*M^2 which would be equivalent to .2 * (3.28^2) lb-ft^2.
But I've never designed a flywheel before and thought I might have missed a lesson a couple decades ago.
Can anyone give me a sanity check? Did they just put the wrong units calculating the weight instead of using the mass?
Thanks all,
-Kirby
Kirby Wilkerson
Remember, first define the problem, then solve it.