fluid mechanics

simple question.

How do I calculate the velocity of water leaving a tap of characteristic length 0.001m. I know the static and atmospheric pressures. I also know density and height. I guess I have to use
velocity x density x characteristic length divided by viscosity

I know this equals the reynolds number and was hoping I could rearrange the formula but don't have the viscosity or Re.

Can I do it another way?

 

[MortenA]

If its not a homework assignment then it should be fairly easy to find the viscosity of water. If your temperature is in the neighbourhood of 15 deg C == 60 deg F then you could use 1 cP

Best Regards

Morten

 

we know velocity = flow rate / fluid flow area (i.e 22/28 * d2), where d = pipe inside diameter.

you collect fixed amount of water eg 10 lit. you note down time required to get 1000 lit. Say time required = 20 second
so flow rate = 1000 lit = 1 m3 / 10sec = 0.1 m3 /s .now you divide the flow rate by flow area , you will get velocity of water.

Pawan kumar (chemical engineer)

 

[MortenA]

Maybe i didnt read the question close enough Pawan Kumar is right. Forget about the Re and do something like the suggested.