KootK
Structural
- Oct 16, 2001
- 18,590
I recently hijacked this thread Link with a discussion about the need for hanger reinforcement for fixing hardware. It's the last four or five posts. I'd like to continue the discussion here. The last statement in that conversation was:
@ Rapt:
I agree that the truss analogy for shear requires top surface loading. It makes sense to me and is supported by pretty much every concrete design example that I can remember seeing. I have to confess that I've never actually thought of this before in such explicit terms. Thanks for bringing it to my attention and contributing to my engineering education!
I also agree that, in any given scenario, there is a load above which explicit hanger reinforcement would be required. However, I also believe that there is also a load below which explicit hanger reinforcement would not be required. Below a certain level, I believe that bottom applied loads can be transmitted, via some form of diagonal tension / shear, into pseudo top applied loads. This would also be the case for your steel example. Below a certain load, one could forgo stiffeners altogether. Please review the attached sketch for my thoughts on the concrete version of this.
As fuzzy "evidence", I submit the following to support my claim that bottom applied loads can in fact be carried to the top of a member via concrete in tensin / diagonal tension / shear:
1) I can't remember many instances of a fixing supplier's manual specifying the need for hanger reinforcement. Sometimes they ask for local reinforcement to improve breakout capacity slightly, but not explicit "take it to the other side" hanger reinforcement.
2) Much of the self weight of a concrete beam itself is transferred to the top surface without explicit hanger reinforcement. Certainly this is the case for a beam with no stirrups which, admittedly, may not fit into the truss shear model analogy. When stirrups are present, the argument gets somewhat murkier.
The greatest trick that bond stress ever pulled was convincing the world it didn't exist.
Rapt said:KootK,
I hope if you have a significant load being applied at the bottom of a concrete, you are providing "hanging reinforcement" to transfer that load to the top of the member. Similar to the way you would in a steel member.
The whole concept of the truss analogy for shear requires this. It assumes that all loads are applied at the top surface and if not then they have to be carried to the top surface using reinforcement. It cannot be carried there by concrete in tension.
@ Rapt:
I agree that the truss analogy for shear requires top surface loading. It makes sense to me and is supported by pretty much every concrete design example that I can remember seeing. I have to confess that I've never actually thought of this before in such explicit terms. Thanks for bringing it to my attention and contributing to my engineering education!
I also agree that, in any given scenario, there is a load above which explicit hanger reinforcement would be required. However, I also believe that there is also a load below which explicit hanger reinforcement would not be required. Below a certain level, I believe that bottom applied loads can be transmitted, via some form of diagonal tension / shear, into pseudo top applied loads. This would also be the case for your steel example. Below a certain load, one could forgo stiffeners altogether. Please review the attached sketch for my thoughts on the concrete version of this.
As fuzzy "evidence", I submit the following to support my claim that bottom applied loads can in fact be carried to the top of a member via concrete in tensin / diagonal tension / shear:
1) I can't remember many instances of a fixing supplier's manual specifying the need for hanger reinforcement. Sometimes they ask for local reinforcement to improve breakout capacity slightly, but not explicit "take it to the other side" hanger reinforcement.
2) Much of the self weight of a concrete beam itself is transferred to the top surface without explicit hanger reinforcement. Certainly this is the case for a beam with no stirrups which, admittedly, may not fit into the truss shear model analogy. When stirrups are present, the argument gets somewhat murkier.
The greatest trick that bond stress ever pulled was convincing the world it didn't exist.