ELFORCE output definition

[arminiusii]

Hi all
I don't understand the ELFORCE card on the CASE CONTROL COMMAND.

If I build 4 nodes, 2 rbe2 and a cbush

GRID,1,,0.,0.,0.
GRID,2,,1.,0.,0.
GRID,3,,1.,0.,0.
GRID,4,,2.,0.,0.
RBE2,10,1,123456,2
RBE2,11,4,123456,3
CBUSH,100,100,2,3,,,,0
PBUSH,100,K,1.00E+10,1.00E+10,1.00E+10,1.00E+10,1.00E+10,1.00E+10

and want to know the ELFORCE on element 100;
apply the force in the x direction on the GRID 1 (constraints on GRID 4) or applied F in the -x direction on the GRID 4 (constrains on GRID 1) it doesn't change the results.

I always obtain that
FORCES IN BUSH ELEMENTS are -1.0 on X direction. What does it mean? That the CBUSH is in compression with 2 forces on his side of 1N? I don't understand how to read the results.

Thanks for your time
Arminius

PS:
for SUBCASE 1
FORCE,1,1,,1.,1.,0.,0.
SPC1,2,123456,4

for SUBCASE 2
FORCE,1,4,,1.,-1.,0.,0.
SPC1,2,123456,1

 

[arminiusii]

I have found the solution you can close the thread, thanks a lot

 

[arminiusii]

And now i'm here again.

I believed to find a solution for Force on CBUSH elements, but now i'm still confusing.

Can someone please explain me the values reported on the F06?
( FORCE-X FORCE-Y FORCE-Z MOMENT-X MOMENT-Y MOMENT-Z )
How to consider the value, positive and negative.

I understand that the forces are in the CBUSH element coordinate system, but if the nodes are coincident how can I understand if the tool is in compression or traction?

Thanks a lot