I have a wire to be soldered into a copper piece. The wire is rated at peak current of 1300 A (peak voltage is 880V). I am interested in how hot the copper piece will get from the current running through the wire, so I can determine the cross section I need to make the copper piece (it will be "T" shaped, with the wire going in one direction, and the other direction being a plug to transfer the current).
I have a few possible methods, though there are others I'm sure I haven't though of.
One I found in Mark's Handbook:
R1 = R2 (1+ alpha*T)
Where R1 is the resistance of the copper piece, R2 is the resistance of the wire, alpha is the temperature coefficient of copper, and T is the difference in temperature.
Resistance of the copper piecce is determined by rho*L/A, where rho is resistivity, L is length, A is cross-sectional area.
Another method I have though of is using conduction. Using the resistivity of the wire, and the current, I found power using i^2*R. Then using this as energy (W), I plugged into the equation
q = k*A*(delta T/L)
where q is Watts, k is thermal conductivity of copper, A is cross-sectional area, delta T is temp. difference, and L is length of the part.
Trying both, the delta T seems to be between 50-70 K, which when I convert to Celsius to check seems very high! Granted this could be due to using too small of a cross sectional area (say 8mm outside diameter and 3 mm inside diameter); however, I thought I would check with you all first.
Any input would be greatly appreciated. Thank you.
I have a few possible methods, though there are others I'm sure I haven't though of.
One I found in Mark's Handbook:
R1 = R2 (1+ alpha*T)
Where R1 is the resistance of the copper piece, R2 is the resistance of the wire, alpha is the temperature coefficient of copper, and T is the difference in temperature.
Resistance of the copper piecce is determined by rho*L/A, where rho is resistivity, L is length, A is cross-sectional area.
Another method I have though of is using conduction. Using the resistivity of the wire, and the current, I found power using i^2*R. Then using this as energy (W), I plugged into the equation
q = k*A*(delta T/L)
where q is Watts, k is thermal conductivity of copper, A is cross-sectional area, delta T is temp. difference, and L is length of the part.
Trying both, the delta T seems to be between 50-70 K, which when I convert to Celsius to check seems very high! Granted this could be due to using too small of a cross sectional area (say 8mm outside diameter and 3 mm inside diameter); however, I thought I would check with you all first.
Any input would be greatly appreciated. Thank you.
