jerryv
Mechanical
- Nov 10, 2000
- 22
I am trying to verify the force to slip of our dual rubber cleated hose puller. Any input would be appreciated!
•We use 16 die springs / 8 per side of the belts. – Spring Rate 241 lb./1/10 in
•Total spring displacement is .5 in.
•Average coefficient of friction of cleated rubber belts - .45 µs
•Maximum spring force 241 (lb. /1/10 in per spring) x .5” (Max Displacement) x 10 = 1,205 lbf
•1,205 lbf x 16 (Total Springs) =19,280.00 lbf.
•19,280.00 lbf x .45 µs = 8,676.00 lbf total force to slip
•We use 16 die springs / 8 per side of the belts. – Spring Rate 241 lb./1/10 in
•Total spring displacement is .5 in.
•Average coefficient of friction of cleated rubber belts - .45 µs
•Maximum spring force 241 (lb. /1/10 in per spring) x .5” (Max Displacement) x 10 = 1,205 lbf
•1,205 lbf x 16 (Total Springs) =19,280.00 lbf.
•19,280.00 lbf x .45 µs = 8,676.00 lbf total force to slip