Let me understand: are you assuming that the hole developed at the Gibault joint is a source of air been sucked by -and into- the pump ?
As for myself I think the "top guns" are right.
A centrifugal pump doesn't suck, being a dynamic machine it even doesn't develop pressures but velocities which are eventually converted to heads and pressures by the volute.
Slurries may cause erosion/corrosion depending on many factors. And the hole in the suction line may be coincidental with other mechanical or hydraulic problems.
As a result dissolved air may be released from the air-saturated water inside the pump provoking "gas binding" and loss of capacity.
Even though dissolved air is 1.7% by vol at 30
oC at atmospheric pressure, and is small at the pump-suction-source conditions, it can become significant if the pressure at the pump's eye is much lower.
If for any reason (hydraulic or mechanical) the pressure drop in the suction line changes with time (slurries behave as non-newtonian fluids), air volumes released in the pump from saturated water may become much more than the 2-3% pumps can generally tolerate without encountering serious mechanical problems.
The following estimation will show the maximum % vol of air that can be developed. The minimum acceptable pressure at the pump's eye would be water's vp= 0.61 psi at 30
o. The corresponding maximum volume and vol % of the dissolved air at this pressure would be, respectively:
1.7*(14.7/0.61) = 41 cc/100 cc H2O
(41/141.5)100 = 29.1% !
I'm sure the experts will comment on this subject for us to learn, in particular when dealing with slurry pumps.