jheidt2543
Civil/Environmental
- Sep 23, 2001
- 1,469
From the IBC 2000, Formula 16-10 load combination:
D + (Lr or S or R) + L + (W or .7E)
Given: D = 20 psf, Lr = 20 psf, S = 20 psf,
An industrial building with a cab operated overhead crane. When looking at the load combinations that include seismic loads, we take the building weight and we take the weight of the bridge crane mechanism (trolley & bridge, but no lifted load) to figure out the seismic shear force, vertical and horizontal for the building as a whole.
Now, look at an individual column supporting the building and the crane (where in this case L = the crane loading on the column; vertical, lateral and transverse).
First, I consider the entire crane load as live load, the trolley, the bridge and the lifted capacity + impact from the single column’s point of view for vertical, lateral and transverse loads.
Secondly, when considering seismic, it seems that the column sees it’s portion of the building seismic load and, when the crane is on the column line in question, ALL of the bridge crane seismic load (trolley & bridge, but no lifted load) divided between the two columns in the line (assuming a clear span crane bay).
So, the combination for the individual column would look like:
D + .75*(Lr + S + L) + .7(E building + E crane) where E crane = total crane mechanism weight used in the seimic base shear equation.
Is this how you all look at it too?
D + (Lr or S or R) + L + (W or .7E)
Given: D = 20 psf, Lr = 20 psf, S = 20 psf,
An industrial building with a cab operated overhead crane. When looking at the load combinations that include seismic loads, we take the building weight and we take the weight of the bridge crane mechanism (trolley & bridge, but no lifted load) to figure out the seismic shear force, vertical and horizontal for the building as a whole.
Now, look at an individual column supporting the building and the crane (where in this case L = the crane loading on the column; vertical, lateral and transverse).
First, I consider the entire crane load as live load, the trolley, the bridge and the lifted capacity + impact from the single column’s point of view for vertical, lateral and transverse loads.
Secondly, when considering seismic, it seems that the column sees it’s portion of the building seismic load and, when the crane is on the column line in question, ALL of the bridge crane seismic load (trolley & bridge, but no lifted load) divided between the two columns in the line (assuming a clear span crane bay).
So, the combination for the individual column would look like:
D + .75*(Lr + S + L) + .7(E building + E crane) where E crane = total crane mechanism weight used in the seimic base shear equation.
Is this how you all look at it too?