Engineer6512
Mechanical
- Nov 4, 2002
- 67
I'm calculating required outdoor air for a vehicle test facility where the vehicles will be running continuously in the space. Here are my calcs - please feel free to comment on anything I might be missing.
CO is the dominant contaminant. Allowable max concentration is 29 mg/m3.
CO generation rate: 11.67 g/min = 11670 mg/min
4 vehicles running: 4 * 11670 = 46680 mg/min
(source ASHRAE applications, chp. 13, table 6 avg of winter emmissions)
Molecular weight, CO: 28
Moles CO per mg: = 0.001/28 = 3.57E-05 mol/mg
T = 298 K
P = 1 atm
R = 0.08206 L*atm/(K*mol)
Volume CO generated per min: = 46680 * (3.57E-05 * 0.08206 * 298 / 1) * (0.001 L/m3) = 0.040768 m3/min
K = 5 (imperfect mixing)
Dilution Air: V = (G/C)*K = (0.040768 m3/min / 29E-06 ppm) * 5 = 7028 m3/min ~ 250000 CFM
Did I miss something here? Or is this really the flow rate I need?
Thanks!
CO is the dominant contaminant. Allowable max concentration is 29 mg/m3.
CO generation rate: 11.67 g/min = 11670 mg/min
4 vehicles running: 4 * 11670 = 46680 mg/min
(source ASHRAE applications, chp. 13, table 6 avg of winter emmissions)
Molecular weight, CO: 28
Moles CO per mg: = 0.001/28 = 3.57E-05 mol/mg
T = 298 K
P = 1 atm
R = 0.08206 L*atm/(K*mol)
Volume CO generated per min: = 46680 * (3.57E-05 * 0.08206 * 298 / 1) * (0.001 L/m3) = 0.040768 m3/min
K = 5 (imperfect mixing)
Dilution Air: V = (G/C)*K = (0.040768 m3/min / 29E-06 ppm) * 5 = 7028 m3/min ~ 250000 CFM
Did I miss something here? Or is this really the flow rate I need?
Thanks!