Eng-Tips is the largest forum for Engineering Professionals on the Internet.

Members share and learn making Eng-Tips Forums the best source of engineering information on the Internet!

  • Congratulations JStephen on being selected by the Eng-Tips community for having the most helpful posts in the forums last week. Way to Go!

DC motor FLA

Status
Not open for further replies.

StanleySmith

Electrical
Joined
Jun 4, 2005
Messages
18
Location
US
hey guys, I'm using a 120/220VAC drive to power a 1/3 HP DC motor. I want to calculate the FLA.
What's the formula??? Can I use this relatioship 1HP =746W =746x1Vx1Amp ?
Thank you,
 
"a 120/220VAC drive to power a 1/3 HP DC motor"

How do you mean? Connecting a DC motor to an AC drive? I do not understand.

Gunnar Englund
--------------------------------------
100 % recycled posting: Electrons, ideas, finger-tips have been used over and over again...
 
Roughly yes! You can use that formula. It would, of course, exclude all the losses (~20%) and it won't describe the starting current.

And Skog's question remains...

Keith Cress
Flamin Systems, Inc.-
 
Sorry, It's a AC-DC converter. AC line voltage is 115/230, and it produces 0-90 VDC/0-180 VDC armature voltage...
 
It depends on what the rated voltage is. If it is 90 V and we assume 80 % efficiency, then your FLA will be something like 250[W]/90[V]/.80 = 3.5 A. If it is 180 V, you will get half of that current.

Is there an excitation winding as well? If so, is it supplied by a separate rectifier - or do you supply it from the main rectifier. In the latter case, you need to add the field winding current to the total.

Gunnar Englund
--------------------------------------
100 % recycled posting: Electrons, ideas, finger-tips have been used over and over again...
 
For the DC motor circuit:
I = Pe/V
were:
Pe = electric power supplied in watts = Pot/EFF
V = motor input voltage
Pot = Mechanical Power output in watts
EFF = Motor efficiency
 
Status
Not open for further replies.

Part and Inventory Search

Sponsor

Back
Top