At 32.2degC, water vapor pressure =36mmHg, so water content in compressed air, mole fraction, at 34bara = 36/(34x760)=0.0014
Initial JT letdown of air from 34bar abs, 32.2degC to atm results in an exit temp of 292degK = 19degC, at which conditions, water content, mole fraction = 16.5/760=0.022, so no condensation initially.
As the tank depressures, tank contents undergo close to isentropic depressurisation, so tank temp drops considerably as pressure drops. At each pressure point, the corresponding exit temp at 1atm continues to drop below 19degC.
To get the temp / press profile for both the exit and tank as tank pressure drops, model this on a process simulator using the Depressure utility routine - you could use an isentropic eff of say 80-90% to approximate this thermodynamically irreversible process. At some point, you may get the exit temp dropping below water freeze point.