cmryu
Petroleum
- Jan 23, 2007
- 22
Hello !
I'm in a very difficult situation to do calculation of reinforcement area in common pad between Two nozzle, this case is not subject to multi- opening requirement as per UG-42.
the result of my calculation is follows.
- Required area : 0.5*d*tr in a single opening case
- Available area : (Dp-d-2tn)*te*f4 multiple of proportion of Pad diameter.
For example
- Avaiable area in Nozzle "A" : 200 cm^2
- Available area in Nozzle "B" : 100 cm^2
* Pad Dia. in Nozzle "A" : 300 mm
* Pad Dia. in Nozzle "B" : 200 mm
Proportion in "A" : 0.6, 300/(300+200)
Proportion in "B" : 0.4, 200/(300+200)
- Applied available are in "A" 300 cm^2 * 0.6 = 180 cm^2
- Applied available are in "B" 200 cm^2 * 0.4 = 80 cm^2
Is this case defined in ASME code requirement.
Regards,