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Combinded Stress Steel Pipe - AISC 13th Ed 1

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RFreund

Structural
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Aug 14, 2010
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A hollow pipe section subject to axial, shear, torsion, and bending in 2 perpendicular directions.
How should the unity check be made in accordance with AISC 13?


I would think it would be Pr/Pc + Mr/Mc + (Tr/Tc + Vr/Vc)^2 where Mr=sqrt(Mx^2+My^2)

However this doesn't seem clear in AISC 13th it actually appears that it should be:
Pr/Pc + Mx/Mc + My/Mc + (Tr/Tc + Vr/Vc)^2
This seems conservative but what do i know?

subscript r = required strength
subscript c = capacity of section

Thanks!

EIT
 
I don't think you add axial/moment unities with shear/torsion.

 
I'm not familiar with your equation but the moments do not add for a pipe, where one stress is maximum the other is zero. put another way, there is no metal whetre the maximums would occur together.

Michael.
Timing has a lot to do with the outcome of a rain dance.
 
The moments on perpendicular axes would be resolved into the combined moment. I was thinking one of the codes showed this for pipe.
 
@JStephen, it was drummed into us at school, logically, you can resolve forces but not moments, you must resolve forces and calculate a new moment, or you can add/subtract the stresses resulting from the moments. This is a must if the moments are caused by horizontal forces at different elevations in different directions. As I said earlier, the maximum stresses due to moments in different directions are not additive because the roundness of the pipe means there is no metal there.

Michael.
Timing has a lot to do with the outcome of a rain dance.
 
I would say use equation H1-1 or H3-6 depending on the magnitude of the torsion.

I can kind of see what Pad is getting at but I think ultimately, if you resolve the forces that are causing moments in different directions, you will simply have one moment on the pipe.
 
I'm really trying to stay within the bounds of AISC 13 unity check (but I wouldn't mind knowing how to 'actually' combine the stress either) and I'm trying to apply H3-6 but I guess the question is what is Mr/Mc or how to apply it? Mr is force resultant or do you need to consider the directions independently?

If you combine the force components into a resultant then solve for the moment isn't that the same as Mr=sqrt(Mx^2+My^2)? Or are am I missing something?



EIT
 
@RFreund, sorry, I didn't mean to screw things up. Your Mr=sqrt(Mx^2+My^2) gives the right answer.

Michael.
Timing has a lot to do with the outcome of a rain dance.
 
Sorry Toad, It is one of those funny cases where an illogical operation is a shortcut to the right answer. I was concerned because I have found several people over the years adding max to max and "failing" a perfectly good pipe. The illogicality of combining moments was drummed into us.

Michael.
Timing has a lot to do with the outcome of a rain dance.
 
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