kjoiner
Mechanical
- Oct 31, 2002
- 462
Hello,
This should be a basic question but I want to double check my moments so I can size a frame member and I haven't done this in a while.
I have a beam, fixed on both ends, 87" long with 2 point loads at 29" and 58". Each point load is 543 lb downward. In reality, my point loads are about 1" further outboard, but this approach seems simpler and more conservative.
I arrived at the end moments using M=Pab^2/l^2. This formula should work for beams where the point loads are at l/3. The end moments calculate to 6998 in-lb.
I'm interested in the maximum bending moment so I cut the beam at 29". The moment calculates to 29(543) - 6998 = 8749 in lb.
On my moment diagram, the moment starts at -6998, then jumps vertically to 8749 at 29". Then the moment curve slopes down, crosses 0 at 43.5" and then reaches max negative moment of -8749 in-lb at 58".
Am I correct that the moment line with rise vertically where the shear is 0 (at 29") since the ends have negative moments?
Thanks,
Kyle
This should be a basic question but I want to double check my moments so I can size a frame member and I haven't done this in a while.
I have a beam, fixed on both ends, 87" long with 2 point loads at 29" and 58". Each point load is 543 lb downward. In reality, my point loads are about 1" further outboard, but this approach seems simpler and more conservative.
I arrived at the end moments using M=Pab^2/l^2. This formula should work for beams where the point loads are at l/3. The end moments calculate to 6998 in-lb.
I'm interested in the maximum bending moment so I cut the beam at 29". The moment calculates to 29(543) - 6998 = 8749 in lb.
On my moment diagram, the moment starts at -6998, then jumps vertically to 8749 at 29". Then the moment curve slopes down, crosses 0 at 43.5" and then reaches max negative moment of -8749 in-lb at 58".
Am I correct that the moment line with rise vertically where the shear is 0 (at 29") since the ends have negative moments?
Thanks,
Kyle