Tek-Tips is the largest IT community on the Internet today!

Members share and learn making Tek-Tips Forums the best source of peer-reviewed technical information on the Internet!

  • Congratulations TugboatEng on being selected by the Eng-Tips community for having the most helpful posts in the forums last week. Way to Go!

(Applied Thermodynamics)__How to calculate the specific volume of water, at 100ºC and 1.5 bar? 3

Status
Not open for further replies.

Nerdy123456

Mechanical
Joined
Sep 19, 2017
Messages
2
Location
PT
The only data in the question is this table:
TermAp_cap1_2_jynlb5.png



Do we have to do an interpolation between the point at 100ºc + 1.014 bar, the point at 110ºC+ 1.433 bar, and the point at 120ºC + 1.985 bar ?

What other suggestions you may have?

Thanks a lot! [2thumbsup] [bigears]
 
I'd use 1.0435x10-3 m3/kg from the sat'd 100o C liquid. The change in density/specific volume on a liquid (water) by compressing it from 1.014 bar to 1.5 bar is nil.

Good luck,
Latexman

To a ChE, the glass is always full - 1/2 air and 1/2 water.
 
NIST gave sat'd properties density = 958.35 lb/m3 and 1.5 bar isobaric properties density = 958.37 lb/m3.

[tiphat]

Good luck,
Latexman

To a ChE, the glass is always full - 1/2 air and 1/2 water.
 
Steamtab
You need not look in to a table, again, once you download this.

 
From NIST webbook. 0.0010434 m3/kg.
 
An alternate method is to use a steam Mollier diagram since it will show the specific volume lines in the superheated region. You may have to interpolate and loose a little accuracy.
 
Status
Not open for further replies.

Part and Inventory Search

Sponsor

Back
Top