mar2805
Structural
- Dec 21, 2008
- 375
Hi!
I neeh help guys.
The pressure formula p=F/A
Lets say that Im standing on a surface that has value of allowable pressure that it can stand of 10kN/m2
My weight is 100kg, wich is equal to 1kN.
Im standing on one foot.
Lets say that the area of my feet thats touching teh graound around 0.3m x 0.05m, wich gives a surface od 0,015m2.
The pressure that Im generating on a surface is 1kn/0,015m2=66,66kN/m2
Is it ok to say that the ground surface that Im standing on, will fail! Since 66,66kN/m2 > 10kN/m2
Lets imagine another situation where you have the same ground surface with allowable pressure of 10kN/m2.
Then I load it with a concrete box wich has dimensions 1,00 x 1,00 x 0,4m (height). Since the density of the concrete is around 25Kn/m3 it will generate a force of F=a x b x c x density wich equals= 1 x 1 x 0,4 x 25=10KN.
If I divide this force with the area that the box is touching the ground I will get an pressure value of 10kN/m2
We can say that the critical value is acchived a that the ground surface will probably fail.
The problem with this is that I cannot simpy visual this.
Me weight Vs. the concrete block
I generate greater pressure on a surface then the concrete block wich is 0,4m thick!
The ground surface will fail faster under my load and not under this concrete block!
?!)"?!
Can someone confirm this?
Thanx!
I neeh help guys.
The pressure formula p=F/A
Lets say that Im standing on a surface that has value of allowable pressure that it can stand of 10kN/m2
My weight is 100kg, wich is equal to 1kN.
Im standing on one foot.
Lets say that the area of my feet thats touching teh graound around 0.3m x 0.05m, wich gives a surface od 0,015m2.
The pressure that Im generating on a surface is 1kn/0,015m2=66,66kN/m2
Is it ok to say that the ground surface that Im standing on, will fail! Since 66,66kN/m2 > 10kN/m2
Lets imagine another situation where you have the same ground surface with allowable pressure of 10kN/m2.
Then I load it with a concrete box wich has dimensions 1,00 x 1,00 x 0,4m (height). Since the density of the concrete is around 25Kn/m3 it will generate a force of F=a x b x c x density wich equals= 1 x 1 x 0,4 x 25=10KN.
If I divide this force with the area that the box is touching the ground I will get an pressure value of 10kN/m2
We can say that the critical value is acchived a that the ground surface will probably fail.
The problem with this is that I cannot simpy visual this.
Me weight Vs. the concrete block
I generate greater pressure on a surface then the concrete block wich is 0,4m thick!
The ground surface will fail faster under my load and not under this concrete block!
?!)"?!
Can someone confirm this?
Thanx!