Mandrill22
Mechanical
- Jul 30, 2010
- 113
I'm trying to figure out what the output died and torque of the motor below would be. I would think it's 6W x 30:1 great ratio at 60 RPM would be:
Torque (N.m) = P / [(2pi*RPM)/60] * Gear Ratio
= (6W / [2pi*60RPM/60]) * 30
= 28.5 NM
However, is the listed RPM the output RPM of the motor, or the RPM after the gearing?
Motor on Aliexpress
Torque (N.m) = P / [(2pi*RPM)/60] * Gear Ratio
= (6W / [2pi*60RPM/60]) * 30
= 28.5 NM
However, is the listed RPM the output RPM of the motor, or the RPM after the gearing?
Motor on Aliexpress