roydm said:
Q1) Should we be selecting a 60 Hz motor and underspeeding it or a 50 Hz motor and overspeeding?
The frequency is insignificant alone. What matters (as far as the motor is concerned) is the voltage and frequency relationship, known as the V/Hz ratio. A motor designed for 460V 60Hz has a V/Hz ratio of 460/60 or 7.67:1. A motor designed for 380V 50Hz is 380/50 or 7.6:1; virtually the same. So the motor is really no different and changing the speed is not the main problematic issue here; but read on...
Q2) Would the 50 Hz option be the same HP motor as the 60 Hz option?
Your HP requirement needs to be driven by the load. For a pump, load is determined by flow (and/or pressure). Determine what you need, then select a motor that makes that work. If, at the relative speed at 50Hz, the motor power is insufficient to provide the flow and pressure you need compared to a design that used a 60Hz motor, then yes, the motor power would need to be higher; ; but read on...
Q3) If you overspeed a 50 Hz motor does the Voltage go over as well or would we set the VFD for 380 Volts at the new top speed?
As stated above, the V/Hz ratio must be maintained. But when using a VFD, it cannot INCREASE the voltage by itself beyond what it gets from the supply. So if you input 380V, the most you can get out is 380V (nominally). When you get to 380V output at 50Hz, then you keep increasing the speed to 60 Hz, you have no more voltage and the V/hz ratio drops. That equates to having a constant kW operation, meaning that your torque now decreases at that 50Hz point forward. If however you can increase the voltage input to the VFD (say to 460V?), the proper ratio can be maintained up to 60Hz. So at 60Hz, your
motor output power (kW) is higher than it would be at 380V
60Hz, but the same if it were 380V 50Hz, just slower. But that too is not the whole story.
In a centrifugal pump system, flow (Q) is directly related to the speed of the pump, but POWER is related to the CUBE of the speed difference. So if, for example, your pump system was designed around a 460V 60Hz motor, running at 50Hz, even if the V/Hz ratio was correct by using 380V at 50Hz, will decrease the flow by the speed difference. 50/60 = 83.3% speed, so flow will drop to .833 of what it would be at 60Hz. If you now speed that motor to 60Hz to get the flow back, but you cannot keep the V/hz ratio correct, the POWER required to do this would increase by the cube of the speed increase, so 120%
3 or 173%. Therefore in order to get the same flow with a motor running over speed, your pump power would need to almost double. This answers your question directly, but it is not necessarily the way to go about this. By simply adding a transformer ahead of a VFD, you can run the system at it's original 60Hz design parameters.
Q4)Would a 10 kV 200 kW motor be the same frame size as a 380 V motor?
I'm not sure anyone makes 200kW 10kV motors. If they do, it
could be smaller, but more likely it will be a larger standard MV motor frame with less winding material.
Q5) What is the relevent cost of a 10 kV motor v/s a 380 Volt one?
MV motors tend to be only a little more or even less for an equivalent power rating, but a 10kV VFD would be 20X the price! One reason is, there really is little relationship to the power rating and the cost to manufacture a MV drive, the expensive issue is in dealing with the voltage level. So for all intents, a 200kW 10kV drive is likely to be a 2000kW 10kV drive, just de-rated to 200kW. I know that for a long time, the smallest 5kV VFD you could buy was 360A, which equated to about 2000HP (1500kW), however most manufacturers would gladly put a nameplate on it telling you it was only a 300HP drive for no extra charge. I suspect the same to be true at 10kV and I would expect to pay about US$250,000.00 minimum (maybe more) for a 10kV VFD, no matter how small.
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