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50/50 Methanol-Water Mixture 2

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ELJ51

Mechanical
Joined
Mar 11, 2014
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Location
US
Does anybody know how to find or calculate the specific heat capacity of 50% Methanol 50% Water mixture? I have a chiller running at -40°F and I need the thermodynamic properties to calculate the load.

Thanks
 
Marks Handbook for Mechanical Engineers.
 
I think that the formula is:
(Cp)mixt= ((Cp*M)methanol+(Cp*M)water)/ (Mmethanaol+Mwater); M stands for mass.
 
Much appreciated!
Thanks!
 
Simple rule of mixtures may not be terribly accurate for a non-ideal mixture.
 
Try to do a web search for this data...often data like this is already published
 
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