Dec 4, 2014 #1 ELJ51 Mechanical Joined Mar 11, 2014 Messages 4 Location US Does anybody know how to find or calculate the specific heat capacity of 50% Methanol 50% Water mixture? I have a chiller running at -40°F and I need the thermodynamic properties to calculate the load. Thanks
Does anybody know how to find or calculate the specific heat capacity of 50% Methanol 50% Water mixture? I have a chiller running at -40°F and I need the thermodynamic properties to calculate the load. Thanks
Dec 5, 2014 #2 willard3 Mechanical Joined Jan 14, 2006 Messages 1,437 Location US Marks Handbook for Mechanical Engineers. Upvote 0 Downvote
Dec 5, 2014 2 #3 chicopee Mechanical Joined Feb 15, 2003 Messages 6,199 Location US I think that the formula is: (Cp)mixt= ((Cp*M)methanol+(Cp*M)water)/ (Mmethanaol+Mwater); M stands for mass. Upvote 0 Downvote
I think that the formula is: (Cp)mixt= ((Cp*M)methanol+(Cp*M)water)/ (Mmethanaol+Mwater); M stands for mass.
Dec 6, 2014 Thread starter #4 ELJ51 Mechanical Joined Mar 11, 2014 Messages 4 Location US Much appreciated! Thanks! Upvote 0 Downvote
Dec 7, 2014 #5 Compositepro Chemical Joined Oct 22, 2003 Messages 7,841 Location US Simple rule of mixtures may not be terribly accurate for a non-ideal mixture. Upvote 0 Downvote
Dec 7, 2014 #6 GHartmann Chemical Joined Nov 15, 2011 Messages 246 Location US Try to do a web search for this data...often data like this is already published Upvote 0 Downvote