So to figure this out....
I will need to determine the amount of distance the particle will travel into the surface to ultimately equal the amount of compression strength the surface has. Meaning, the particle will indeed be embedded into the surface and the key will be how far. Too far being...
Volume=
25 um diameter = 9.8425 x 10^-4 diameter in inches
4/3 * pi * r^3 = volume of 4.992 * 10^-10 in^3
Weight = 1.522 * 10^-10 lbs = 6.921 * 10^-11 kg
Am I correct, or did I get a different number in there
You are correct. The surface would dent some. As the material builds up, the rigidity would increase as well. There is a lot of energy to absorb. The tricky part is with one particle after another hitting. This is a cold spray method. 750 m/s forming a metal layer. Guess I would have to...
rb1957 is pretty close.
I have a small particle that is completely deforming. In technical terms, the particle is going "splat". :)
I have converted all numbers over into the same system. I was just giving the raw data that I used. I also am looking for the correct formula(s) to see if...
Hello. This is my first time on this site. I am hoping to utilize the experience on here. I have a scenario that I have tried to calculate, but I am not sure of my results. Here is what I have.
I have a material with the weight of .305 lbs/ in^2. Size is 25um. For calculation...
