For the triaxial CD test, (σ_1^')/(σ_3^' )= (1+sin〖∅'〗)/(1-sin〖∅'〗 )
The term on the right side of the equaition resembles the Kp lateral earth pressure coefficient.
I want to understand why is this so. Is it because Kp relates the vertical force to horizontal force, and here at the triaxial...