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sorting an array

sorting an array

sorting an array

(OP)
Hi,

I want to sort an array by colunm 2 swopping the values of the whole row each time a sweep is made. for some reason it will sort the input array (given at the bottom) if i only want to swop the values in colum 2 but when i add the code to swop the other columns it gets mixed up. Any help would be appreciated. this is my code.

        PROGRAM SORT_NODES
        INTEGER:: I,J,SWOPS,NODE,NUM
        REAL:: INPUT(10,4),TEMP,TEMPY,TEMPZ,TEMPN,X,Y,Z
        OPEN(UNIT=40,FILE='input.txt',STATUS='old')
C        OPEN(UNIT=20,FILE='temp.txt',STATUS='old')
        OPEN(UNIT=30,FILE='newinput.txt',STATUS='unknown')
        N=10
        DO 70 K=1,N
        READ(40,*)NODE,X,Y,Z
        INPUT(K,1)=NODE
        INPUT(K,2)=X
        INPUT(K,3)=Y
        INPUT(K,4)=Z
70     CONTINUE
80      CONTINUE
               DO 90 J=1,N
                         IF (INPUT(J,2).GT.INPUT(J+1,2))THEN
C                        swop x values
                                   TEMP=INPUT(J,2)
                                   TEMPN=INPUT(J,1)
                                   TEMPY=INPUT(J,3)
                                   TEMPZ=INPUT(J,4)
                                   INPUT(J,1)=INPUT(J+1,1)
                                   INPUT(J,2)=INPUT(J+1,2)
                                   INPUT(J,3)=INPUT(J+1,3)
                                   INPUT(J,4)=INPUT(J+1,4)
                                   INPUT(J+1,2)=TEMP
                                   INPUT(J+1,1)=TEMPN
                                   INPUT(J+1,3)=TEMPY
                                   INPUT(J+1,4)=TEMPZ
C
                        ENDIF
90            CONTINUE
          DO 100 J=1,N
          IF (INPUT(J,2).LT.INPUT(J+1,2))THEN
              GOTO 100
              ELSE
              GOTO 80
              ENDIF
100            CONTINUE
         DO 110 i=1,N
         NUM=INT(INPUT(i,1))
         WRITE(30,*)num,INPUT(i,2),INPUT(i,3),INPUT(i,4)
C        DO 110 I=4,10
C        WRITE(20,*)NODE
C        INPUT(I,1)=NODE
C        INPUT(I,2)=X
C        INPUT(I,3)=Y
C        INPUT(I,4)=Z
110     CONTINUE
        STOP
        END PROGRAM SORT_NODES

And my sample input file:

   5867,       87.74,     -71.2088,     -6.77245
   5868,      22.9593,      110.643,     -6.52507
   5869,     -111.578,      -17.872,     -232.855
   5870,     -3.09514,      112.958,     -144.851
   5871,      108.945,      29.9988,     -4.97048
   5872,       24.106,     -110.399,     -191.622
   5873,     -34.0516,      107.747,     -227.898
   5874,     -112.632,     -9.11318,     -235.768
   5875,     -108.809,     -30.4893,     -235.772
   5876,      111.631,      17.5379,     -38.9666
   5877,     -24.8057,      110.244,      -7.1432
   5878,     -23.8124,      110.463,     -228.046
   5879,      12.1292,      112.347,     -6.46787
Replies continue below

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RE: sorting an array

Hi Mullins

Your problem is very trivial, your do loops DO 90 J=1,N and DO 100 J=1,N cause an array out of bounds error on the very next line in each case you try to reference INPUT(J+1,2) which means when J equals N you try to reference INPUT(N+1,2)which obviously doesn't exist. Changing the loops to J=1,N-1 corrects the error.

However I must add that your code is basically the notorious "BUBBLE" sort method, it's okay for very small arrays (<12) only. The method is probably the most inefficient algorithm in the whole history of computer programming ! The run time for this method increases exponentially with the size of the array and only a relatively modest size array can bog your computer down for hours or even days!! Any decent book on programming techniques should provide the source code for the very excellent HEAP or SHELL sort methods.

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