ARRAY FUNCTION 1

Dim Ans()=ArrayFunct(InputArray())
This is not syntactically correct. You cannot call a function inside of a dim statement. Nor will the Redim statment work in this construct either. However, you may be able to do the following, as you've assigned some dimentions to InputArray
Ans = ArrayFunct(InputArray)

Inside your function, it will be necessary to assign dimensions to IntermediateArray before you can use it as a return value.

To provide examples, and/or suggestion to help you get the job done, it would helpful to know what the job is.

While you are using dynamic arrays be carefull with using ReDim statment. This statment always clear all your array. To keep your array use following. The following code show how to increase your array with protecting all array data.

'ReDim Preserve MyArray(UBound(MyArray)+1)'


Vlado

Friends,
Let me put my problem once again. I am programming a problem requiring matric operation. the size of matrix is not known and size of output matrix is also not known. So it will be like

Dim InputMatrix() as double
Dim Output() as double

Sub Main()
Dim NOE as integer
'....
'......
'Determination of a variable NOE
'.....
ReDim InputMatrix(NOE, NOE) as double
'Now matrix operation function is called as
OutputMatrix=MatrixFunction(InputMatrix)
'......
'....
End Sub

Function MatrixFunction(ABC as variant) as Double()
'Now the result of this function will depend upon
'the size of input matrix or ABC variant
' I tried this
Dim NOS as integer
NOS=2*ubound(ABC,1)
Redim IntermediateMat(NOS,NOS,NOS)
'Calculation of intermediateMat
'Now the problem is how to assign this intermediateMat
'as the result of this function



End Function

Not sure about using a Function but you can certainly have a sub with an input and an output array, eg this works


Private Sub Command1_Click()
Dim ABC(), DEF() As Double
ReDim ABC(3, 4)
MatrixFunction ABC(), DEF()
Debug.Print ABC(UBound(DEF, 1), UBound(DEF, 2))
End Sub

Sub MatrixFunction(ABC() As Variant, DEF() As Double)
ReDim DEF(UBound(ABC, 1), UBound(ABC, 2))
End Sub

A function should be able to handle it. Try something like this: