×
INTELLIGENT WORK FORUMS
FOR ENGINEERING PROFESSIONALS

Contact US

Log In

Come Join Us!

Are you an
Engineering professional?
Join Eng-Tips Forums!
  • Talk With Other Members
  • Be Notified Of Responses
    To Your Posts
  • Keyword Search
  • One-Click Access To Your
    Favorite Forums
  • Automated Signatures
    On Your Posts
  • Best Of All, It's Free!

*Eng-Tips's functionality depends on members receiving e-mail. By joining you are opting in to receive e-mail.

Posting Guidelines

Promoting, selling, recruiting, coursework and thesis posting is forbidden.

Students Click Here

trying to understand trim() function in MATLAB

trying to understand trim() function in MATLAB

trying to understand trim() function in MATLAB

(OP)
I have just followed the trim() example in Matlab documentttion but I kind of strugling to understand how the equilibrium point is found for the second case where x = [1;1] and u=[1;1].

The example is as follow:
state space in simulink:
A = [-0.09 -0.01; 1 0];
B = [ 0 -7; 0 -2];
C = [ 0 2; 1 -5];
D = [-3 0; 1 0];

then
[x,u,y,dx,options] = trim('sys') % calling simulink model
fir example is to find the equilibrium point of the system. the answer, as expected, x = [0;0]and u = [0;0] as they make derivative of x =0
However the second example states that if another point is given, like x=[1;1] and u =[1;1]

the answer is x = [0;0] and u = [1/3;0].

I was able to calculate manually the poitn x = [0;0] using the state space equation but I CANNOT get the "u"?... How to calculate this "u"?
any clue please?

Red Flag This Post

Please let us know here why this post is inappropriate. Reasons such as off-topic, duplicates, flames, illegal, vulgar, or students posting their homework.

Red Flag Submitted

Thank you for helping keep Eng-Tips Forums free from inappropriate posts.
The Eng-Tips staff will check this out and take appropriate action.

Reply To This Thread

Posting in the Eng-Tips forums is a member-only feature.

Click Here to join Eng-Tips and talk with other members! Already a Member? Login



News


Close Box

Join Eng-Tips® Today!

Join your peers on the Internet's largest technical engineering professional community.
It's easy to join and it's free.

Here's Why Members Love Eng-Tips Forums:

Register now while it's still free!

Already a member? Close this window and log in.

Join Us             Close