## Compression of gas spring

## Compression of gas spring

(OP)

Hi all,

I have a quetion about the compression of a gas spring like the one in the picture .

We see that there are energy-losses (hysteresis) if we deflect the gas spring. So, for example, if we load the gas spring, this costs us 100J, but in unloading the gas spring 'only' returhs 80J. So the question is: where did the 20J go?

We initially thought that this energy is lost in fiction between the cylinder and the seal. However, the manufacturer suggested that this energy may be lost in heat generation due to the compression of the gas (nitrogen) inside the gas spring. I want to check this mathematically, but I am not sure whether I do this correctly.

Assume that we have a starting situation, in which:

Volume = V0 = 0.006 L

Pressure = P0 = 180 bar

Temperature = T0 = 293 K

Then we defect/compress the gas spring, to a situation in wich:

Volume = V1 = 0.0036 L

Pressure = P1 = ?

Temperature = T1 = ?

Now I want to know the amount of energy in Joules that is 'lost' in this compression.

What I did is:

Calculate P1 using P1=P0*(V0/V1)^gamma, in which gamma=cp/cv=1.4 --> P1 = 368 bar

Calculate T1 using T1=(P1*V1)/(P0*V0)*T0 --> T1 = 359 K

Calculate the amount of nitrogen gas inside the gas spring (in moles) using n=(P*V)/(R*T) --> n = 0.044 mol

Calculate the mass of the nitrogen gas inside the gas spring (in kg) using m=M*n --> m = 0.616*10^-3 kg

Calculate the energy that is 'lost' in heating the nitrogen during compression using Q=c*m*(T1-T0) --> Q = 42J

Is my calculation correct? How should I interpretate this result?

Deflecting/compressing the gas spring to its full stroke costs 60J. Does this mean that 42J out of this 60J is 'used' to heat the nitrogen during compression?

And is this energy 'lost', as in, does the gas spring return this energy in unloading?

Thank you in advance!

Bas

I have a quetion about the compression of a gas spring like the one in the picture .

We see that there are energy-losses (hysteresis) if we deflect the gas spring. So, for example, if we load the gas spring, this costs us 100J, but in unloading the gas spring 'only' returhs 80J. So the question is: where did the 20J go?

We initially thought that this energy is lost in fiction between the cylinder and the seal. However, the manufacturer suggested that this energy may be lost in heat generation due to the compression of the gas (nitrogen) inside the gas spring. I want to check this mathematically, but I am not sure whether I do this correctly.

Assume that we have a starting situation, in which:

Volume = V0 = 0.006 L

Pressure = P0 = 180 bar

Temperature = T0 = 293 K

Then we defect/compress the gas spring, to a situation in wich:

Volume = V1 = 0.0036 L

Pressure = P1 = ?

Temperature = T1 = ?

Now I want to know the amount of energy in Joules that is 'lost' in this compression.

What I did is:

Calculate P1 using P1=P0*(V0/V1)^gamma, in which gamma=cp/cv=1.4 --> P1 = 368 bar

Calculate T1 using T1=(P1*V1)/(P0*V0)*T0 --> T1 = 359 K

Calculate the amount of nitrogen gas inside the gas spring (in moles) using n=(P*V)/(R*T) --> n = 0.044 mol

Calculate the mass of the nitrogen gas inside the gas spring (in kg) using m=M*n --> m = 0.616*10^-3 kg

Calculate the energy that is 'lost' in heating the nitrogen during compression using Q=c*m*(T1-T0) --> Q = 42J

Is my calculation correct? How should I interpretate this result?

Deflecting/compressing the gas spring to its full stroke costs 60J. Does this mean that 42J out of this 60J is 'used' to heat the nitrogen during compression?

And is this energy 'lost', as in, does the gas spring return this energy in unloading?

Thank you in advance!

Bas

## RE: Compression of gas spring

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## RE: Compression of gas spring

## RE: Compression of gas spring

Yes, P goes up and V goes down. And the product changes and hence the temperature changes.

n stays the same and so does R.

So P1V1/T1 = P2V2/T2

= = = = = = = = = = = = = = = = = = = =

P.E. Metallurgy, consulting work welcomed

## RE: Compression of gas spring

Remember - More details = better answers

Also: If you get a response it's polite to respond to it.

## RE: Compression of gas spring

There will be a 20%+ error in volume at P2, if you do not use real gas EOS.

https://www.chemguide.co.uk/physical/kt/realgases....

P1V1/T1 * z1 = P2V2/T2* z2

P1 V1 / T1 * Z1 = P2 V2 /T2 * Z2

z at 368 bar 360°K is 1.22

1.04 at 180 bar 293°K.

http://www.peacesoftware.de/einigewerte/stickstoff...

A black swan to a turkey is a white swan to the butcher ... and to Boeing.

## RE: Compression of gas spring

When the air is heated from compression heat transfer to the walls of the piston starts - and that is not returned. The other stuff mention (compressability etc) should work "both ways" so losses from friction in the piston and heat loss when the compressed air is warmer should account for the difference. One way of check could be to do several compression decompression cycles rapidly. If the energy loss appears to be reducing then i would say it confirms this theory. It will not drop to zero because a part of it is friction and also because heat loss to the ambient atm starts when the piston itself is heated.

Best regards, Morten

--- Best regards, Morten Andersen

## RE: Compression of gas spring

A black swan to a turkey is a white swan to the butcher ... and to Boeing.