Polygon driven by 2 equations

You seem to be missing a variable inside the sin and cos brackets, at a guess. should be something like sin(4*t*360deg) where t is a vector length 35

Cheers

Greg Locock


New here? Try reading these, they might help FAQ731-376

hello Greg
Many thanks for your answer, and yes I'm new,
the formula is written on the ISO pdf like this
x' = Dm/2 x cos ζ - 2 x e x cos(2ζ) + e x cos(4ζ)
y' = Dm/2 x sin ζ + 2 x e x sin(2ζ) + e x sin(4ζ)
Dm and e depends of the size of the toolholder, as example DM= 35 mm, e= 1.12 mm, it give a polygonal shape with 6 interconnected arcs with 2 different sizes. the small ones in a range of 14 degrees each one, and the others on range of 106 degrees each one, and they form a 360 degrees polygonal shape. I already done this on SOLIDWORKS in the past, if ζ= 360° we get the whole shape, and if we change it to 180° we get only the half of the shape, we can also replace ζ by PI, on CATIA I'm stuck.
and many thanks in advance for any answer.