Polygon driven by 2 equations
Polygon driven by 2 equations
(OP)
Hi
I'm trying to design a polygon based on 2 equations, it's for a Capto tool holder, it's easy in other software like Solidworks or Inventor, but I don't know how to do inside Catia, I have tried lot of combination like setting up 2 parameters for e= 1.12 and D= 35 or replacing them directly without success, I still get errors.
Thanks very much for your help
x = D / 2 * cos(360deg) - 2 * e * cos(2 * 360deg) + e * cos(4 * 360deg)
y = D / 2 * sin(360deg) + 2 * e * sin(2 * 360deg) + e * sin(4 * 360deg)
I'm trying to design a polygon based on 2 equations, it's for a Capto tool holder, it's easy in other software like Solidworks or Inventor, but I don't know how to do inside Catia, I have tried lot of combination like setting up 2 parameters for e= 1.12 and D= 35 or replacing them directly without success, I still get errors.
Thanks very much for your help
x = D / 2 * cos(360deg) - 2 * e * cos(2 * 360deg) + e * cos(4 * 360deg)
y = D / 2 * sin(360deg) + 2 * e * sin(2 * 360deg) + e * sin(4 * 360deg)
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RE: Polygon driven by 2 equations
Cheers
Greg Locock
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RE: Polygon driven by 2 equations
Many thanks for your answer, and yes I'm new,
the formula is written on the ISO pdf like this
x' = Dm/2 x cos ζ - 2 x e x cos(2ζ) + e x cos(4ζ)
y' = Dm/2 x sin ζ + 2 x e x sin(2ζ) + e x sin(4ζ)
Dm and e depends of the size of the toolholder, as example DM= 35 mm, e= 1.12 mm, it give a polygonal shape with 6 interconnected arcs with 2 different sizes. the small ones in a range of 14 degrees each one, and the others on range of 106 degrees each one, and they form a 360 degrees polygonal shape. I already done this on SOLIDWORKS in the past, if ζ= 360° we get the whole shape, and if we change it to 180° we get only the half of the shape, we can also replace ζ by PI, on CATIA I'm stuck.
and many thanks in advance for any answer.