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Does A Large Eulers Value Also Equal A Large Youngs Modulus?

Does A Large Eulers Value Also Equal A Large Youngs Modulus?

(OP)
Hi all

I was wondering if anyone could help with determining whether a statement regarding compressive column testing is valid or not.

2 x Columns were loaded compressively (same dimensions, same K values), the results revealed:-
Column A has a Eulers Critical Load of 83525N and a Youngs Modulus of 2284N/mm^2
Column B has a Eulers Critical Load of 65493N and a Youngs Modulus of 1791N/mm^2

Would it be correct to say that since column A had a greater Youngs Modulus you would expect column A to also have a greater critical load when compared to column B?

Would this be a valid statement?

Thank you.

RE: Does A Large Eulers Value Also Equal A Large Youngs Modulus?

Would this be a school question? While Euler's theories are important for understanding stability and column buckling, there's a reason they weren't used for the first couple hundred years after he developed them - they fail to account for lots of other aspects of a column and lots of columns analyzed with it initially failed. I hope this isn't for an actual design...

RE: Does A Large Eulers Value Also Equal A Large Youngs Modulus?

(OP)
r13 & phamENG

R13 - I already know Eulers equation but thank you.

PhamENG - No it is a school related question but i was thinking about whether the statement would be true or not.

So your opinion on the actual question is?

RE: Does A Large Eulers Value Also Equal A Large Youngs Modulus?

Your answer lies in the equation, noting the relationship between Pcr and E, with all other terms are identical for both columns.

RE: Does A Large Eulers Value Also Equal A Large Youngs Modulus?

Are you trying to confirm the proportionality of the modulus of elasticity with the critical buckling load? That's not a matter of opinion at all. As r13 said - it's in the equation.

RE: Does A Large Eulers Value Also Equal A Large Youngs Modulus?

(OP)
r13 & phamENG

It has just hit me, you are correct it is in the Equation.

Thank you.

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