Understanding Modulus of Toughness

Based on the information you provided, some of the things don't make sense.

1. My stress strain curve is represented by a straight line function.
2. ..7.867 (which is the strain value of my material at failure)
3. Stress = 8.8771 * Strain
4. Toughness = 4.43855ε2 = 275
5. Main query: Units of toughness?

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1. How did you come up with this conclusion? Because, stress-strain curves for some typical woods I found on google definitely shows a plastic region.

2. Based on your straight line assumption (which I found highly doubtful), If I compare the failure strain of wood which is 7.88% with a measly 2% yield strain of 60 ksi steel, the question that comes to mind is, why the heck aren't we using wood as reinforcement in compression members such as columns?

3. Not only this, it also give a superior ultimate strength which according to following equation will be.
Stress = 8.8771 (assuming the unit of E is GPa) x 1000 x 7.88/100 = 700 MPa = 100 ksi approx.
One can say, steel has higher ductility than wood, then again, we can use this where ductility is not a requirement (being a devil's advocate here).

Again to reiterate, I found the intimated behavior in your point no. 1 to 3 highly doubtful.

4. Seems like, you forgot to divide the strain with 100 while calculating this.

5. Basically toughness is defined as the work done per unit volume and is equals to the area under the stress-strain curve. Which, in your case is equals to area of triangle = StessxStrain/2 = Magnitude (N/mm2)x(unitless) = N/mm2.
Above can also be expressed as = (N/mm2)x mm/mm = N-mm/mm3 = Workdone/Volume

Disclaimer: I've never worked on (or even studied) a wood structure, thus, my comments are solely based on common sense and knowledge of mechanical properties of materials other than wood.

(N/mm²)%