Ideal Gas Calculation
Ideal Gas Calculation
(OP)
An oxygen plant is supplying 1200 Nm3/h of nitrogen at 7 bars for miscellaneous gas as by-product. For the end users, they require nitrogen at 4 bars.
Now the consumption of nitrogen is already at 1100 Nm3/h but at 4 bars. If I convert the end user consumption at 7 bars, I will get 733.33 Nm3/h of nitrogen, assuming no temperature change. If this will be the case, then I have approximately 460+ Nm3/h of nitrogen left.
If I add a load of not more than 460 Nm3/h at 6 bars, will my original supply of nitrogen suffice?
Thanks!
Now the consumption of nitrogen is already at 1100 Nm3/h but at 4 bars. If I convert the end user consumption at 7 bars, I will get 733.33 Nm3/h of nitrogen, assuming no temperature change. If this will be the case, then I have approximately 460+ Nm3/h of nitrogen left.
If I add a load of not more than 460 Nm3/h at 6 bars, will my original supply of nitrogen suffice?
Thanks!
RE: Ideal Gas Calculation
Katmar Software - AioFlo Pipe Hydraulics
http://katmarsoftware.com
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RE: Ideal Gas Calculation
Now if I add another load which is at 2 bars at around 500 Nm3/h will it suffice?
RE: Ideal Gas Calculation
Good Luck,
Latexman
Pats' Pub's Proprietor
RE: Ideal Gas Calculation
Kindly consider Nm3 as the moles supplied.
They will remain constant.
Only the actual volumetric flow rate will change.
For example,
1 pound mole = 379 Standard ft3
Standard ft3 means at 1 atm and 60 Deg. F
Similarly Normal ft3 means at 1 atm and 32 Deg. F.
Kind Regards,
Muhammad Waqas,
Process Engineer from Pakistan