Gas Dilution
Gas Dilution
(OP)
I have a dry air at 3040 Nm3/h 30 deg C and 5 bars (abs), now we want to make it to 97%N2 by adding dry nitrogen gas at the same gas parameters. We need to decrease the O2 level of the fluidizing unit in order to decrease the chance of copper concentrate sintering after drying it. Now, how much dry nitrogen will we add to achieve 97%N2?
RE: Gas Dilution
Let Q-N2 is additional Nitrogen required.
(Q-N2 + 0.79 Q-air) / (Q-N2 + Q-air) == 0.97
Q-N2 = Q-air * (0.97 - 0.79) / (1-0.97)
Q-N2 = 3400 * 0.18 / 0.03 = 18240
If the required concentration is on mass basis, the required Nitrogen will be significantly different. It is so, let me know.
RE: Gas Dilution
Since you would be consuming 18,240 Nm3/hr of N2 for what originally is a 3,040 Nm3/hr flow, why not just go the other way and flow pure N2 with a little bit of dilution air? I calculate you would need 2,624 Nm3/hr of pure N2 and 416 Nm3/hr air to achieve 97% N2. That will let you keep your original 3,040 Nm3/hr flow rate. If you must consume all 3,040 Nm3/hr of air (blower constraints, etc) and want to keep the 3,040 Nm3/hr total flow rate to the fluidizer, you could just bleed the excess air (~2,624 Nm3/hr), which would be far less than the 18,240 Nm3/hr bleed required if injecting N2 like in your OP.
RE: Gas Dilution
RE: Gas Dilution
The set-up will be:
There will be a gas receiver before the fluidization. In the gas receiver, we planned to mix it with nitrogen to dilute the O2, and discharge it to the hoppers at the same parameters.
RE: Gas Dilution