Derivatives
Derivatives
(OP)
Hello All.
How do I solve the power of e , I circled in image below? what is Xdx?

Thank you.
How do I solve the power of e , I circled in image below? what is Xdx?

Thank you.
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RE: Derivatives
RE: Derivatives
Looks like the temperature of a gas in a long pipe that's being cooled or heated along its length.
Cheers
Greg Locock
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RE: Derivatives
RE: Derivatives
> The units don't balance as written
> What do you mean by "solve"?
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RE: Derivatives
RE: Derivatives
TTFN (ta ta for now)
I can do absolutely anything. I'm an expert! https://www.youtube.com/watch?v=BKorP55Aqvg
FAQ731-376: Eng-Tips.com Forum Policies forum1529: Translation Assistance for Engineers Entire Forum list http://www.eng-tips.com/forumlist.cfm
RE: Derivatives
RE: Derivatives
Dik
RE: Derivatives
Again, OP, what do you mean by "solve the exponential value?"
TTFN (ta ta for now)
I can do absolutely anything. I'm an expert! https://www.youtube.com/watch?v=BKorP55Aqvg
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RE: Derivatives
The numerator and denominator of the exponential argument both have units of watts per degrees Kelvin (W/K), so the argument ends up dimensionless.
Numerator = U D dx = (W/m^2*k) * (m) *(m) = W / K
Denominator = m-dot * cp = (kg/sec) * (Joule/[kg*K]) = Joule / [sec*K]) = W / K
=====================================
(2B)+(2B)' ?
RE: Derivatives
RE: Derivatives
Cp is apparently referring to specific heat capacity (at a constant pressure) which would have SI units J/[kg*K] (I don't know what specific units were intended to accompany the value listed 1800)
=====================================
(2B)+(2B)' ?
RE: Derivatives
TTFN (ta ta for now)
I can do absolutely anything. I'm an expert! https://www.youtube.com/watch?v=BKorP55Aqvg
FAQ731-376: Eng-Tips.com Forum Policies forum1529: Translation Assistance for Engineers Entire Forum list http://www.eng-tips.com/forumlist.cfm