×
INTELLIGENT WORK FORUMS
FOR ENGINEERING PROFESSIONALS

Are you an
Engineering professional?
Join Eng-Tips Forums!
• Talk With Other Members
• Be Notified Of Responses
• Keyword Search
Favorite Forums
• Automated Signatures
• Best Of All, It's Free!

*Eng-Tips's functionality depends on members receiving e-mail. By joining you are opting in to receive e-mail.

Posting Guidelines

Promoting, selling, recruiting, coursework and thesis posting is forbidden.

Jobs

(OP)
Dear eng-tips members :

Please kindly help me out in this confusing power calculation equation.

There is some different shape of anchor impellers. Someone may design the anchor impeller D/T ratio range from 0.7~0.85, and the shape may be different from the usual

anchor type. For example, the liquid level may immerse half of the anchor height(H), and by the equation you provide bellow, is any limitation to adopt this equation

Np(laminar) =113 (D/(T-D)) (H/D) (W/D) (n/2)

P = Np(laminar) * Visc * N^2 * D^3

And, what is the relation between the pumping number Nq = Q/(N * D^3) and power number, is it means the increasing D may generate more Q (pump rate), so that the

agitation efficiency will get much better(more fluid in the vessel can pumping up from bottom through the top ?).

May you please kindly help me with some light or hint ?

Thank you so much.

Red Flag This Post

Please let us know here why this post is inappropriate. Reasons such as off-topic, duplicates, flames, illegal, vulgar, or students posting their homework.

Red Flag Submitted

Thank you for helping keep Eng-Tips Forums free from inappropriate posts.
The Eng-Tips staff will check this out and take appropriate action.

Close Box

Join Eng-Tips® Today!

Join your peers on the Internet's largest technical engineering professional community.
It's easy to join and it's free.

Here's Why Members Love Eng-Tips Forums:

• Talk To Other Members
• Notification Of Responses To Questions
• Favorite Forums One Click Access
• Keyword Search Of All Posts, And More...

Register now while it's still free!