I am having trouble in trying to calculate the Aluminum (Al) wt. in the liquid alum that is dose at one of our treatment plants. The alum (Al2(SO4)3.18H2O ((48%) - Molecular wt. 666.132) daily dosing wt is 101.63 kg/d. If so would the Al (MW =27) daily dosing wt. be = 101.63*2*(27/666)= 8 kg/d? (factor of 2 is because 2 Moles of Al in Alum).
Thanks in advance.