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Change specific array elements from an array column

Change specific array elements from an array column

Change specific array elements from an array column

The following question is a repost to this FORTRAN dedicated forum (sorry about that)

Hello all,

although it might sound trivial to more experienced users, I am trying to create a code in FORTRAN (preferably f90 or higher) of a n series x 2 columns matrix, where a condition on some elements of column 1, will change the corresponding elements of column 2 (i.e. only those that have the same "i" with the elements affected by the condition). So far I have managed to do this by creating two (2) column arrays containing the elements and by using a simple "where" command I did what I wanted. Could someone please try to inform me how to perform the same job but without spliting the array into two sub-arrays?

Working example code of what I did follows:

CODE --> 95

program test
    implicit none

    elem = 10      


    do i=1,10
        end do

    do j=1,10
        end do

where (A>=3 .and. A<=6) B = 1


end program test 

Thank you in advance for your kind assistance.
Replies continue below

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RE: Change specific array elements from an array column


program q
    integer :: c(10,2), i, j 
    c(:,1) = (/(i,i=1,10)/)    ;    c(:,2) = 0    
    write(*,'(I2,2x,I2)') ( (c(i,j),j=1,2), i=1,10 )
    where ( c(:,1) >=3 .and. c(:,1) <=6 )  c(:,2) = 1
    write(*,'(I2,2x,I2)') ( (c(i,j),j=1,2), i=1,10 )
end program q 

RE: Change specific array elements from an array column

Hi gsal! I found it myself and posted my reply to the other thread. Just when I was thinking to join this thread and delete my post, I came across your reply. Nice coding there mate! Thank you very much for your effort!

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