## Reply to thread 406-282835

## Reply to thread 406-282835

(OP)

Hello

I also am trying to find the maximum and minimum sizes over pins for an external DIN 5480 spline. I am using DIN 5480:2006 parts 1 and 2. In DIN 5480-1:2006 section 10.12 of this standard it talks about using DIN 5480-15 to calculate these sizes, this is not available to us. It also suggests that it can be done using the deviation factors as described in DIN 5480-2, however no explanation of how this is achieved is given.

In DIN 5480-1:2006 section 9.1 there is given an example of a W120x3x38x8f side fit spline. I have been trying to find M1

DIN 5480-1:2006 section 10.12 tells us the deviation of the measurements over measuring circles is A

Obviously this isn't enough on it's own. So far the closest I have managed to come is to apply A

I don't believe this is right, where am I going wrong?

I also am trying to find the maximum and minimum sizes over pins for an external DIN 5480 spline. I am using DIN 5480:2006 parts 1 and 2. In DIN 5480-1:2006 section 10.12 of this standard it talks about using DIN 5480-15 to calculate these sizes, this is not available to us. It also suggests that it can be done using the deviation factors as described in DIN 5480-2, however no explanation of how this is achieved is given.

In DIN 5480-1:2006 section 9.1 there is given an example of a W120x3x38x8f side fit spline. I have been trying to find M1

_{max}and M1_{min}for this spline using the deviation factor. The target sizes from the example are Max 126.017, min 125.956.DIN 5480-1:2006 section 10.12 tells us the deviation of the measurements over measuring circles is A

_{M1}=A_{e}*A*_{M1}= -0.04256Obviously this isn't enough on it's own. So far the closest I have managed to come is to apply A

_{M1}to the f8 limit dimensions of the 120 shaft i.e. -0.036/-0.090. This gives an answer of max 126.016, min 125.962.I don't believe this is right, where am I going wrong?

## RE: Reply to thread 406-282835

## RE: Reply to thread 406-282835

Dk=6 (pin dia.)

Mdk=126,095

A*=1,52

8f: -0,051/-0,091

The min measurement: 126,095-0,091*1,52=125,96

The max measurement: 126,095-0,051*1,52=126,02

The same for the span measurement:

7 (no of teeth)

M7=59,710

A*=0,866

8f: same

The min measurement: 59,710-0,091*0,866=59,63

The max measurement: 59,710-0,051*0,866=59,67

## RE: Reply to thread 406-282835

Thank you, that looks like what I am trying to find. Please can you tell me, where did you get the values for 8f? Is it the DIN 5480-15:2006 that I have not got?

## RE: Reply to thread 406-282835

## RE: Reply to thread 406-282835

_{s}+T_{eff}and A_{s}+T_{G}as per the example shown. Thank you.Think I could have looked at this till the cows came home and never got it.