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How to initialize array dynamically to find out grid independent solution

How to initialize array dynamically to find out grid independent solution

How to initialize array dynamically to find out grid independent solution

(OP)
Hi All,

I am trying to figure out how to allocate the size for Array dynamically, as in I want it to be from 0 to a Number till grid independent solution is reached by a Condition.

So below is my program, I run it many time for different values of N. But then I don't want to do this, could you please help me with this


Thank You!

P.S: I have tried different ways but then since the entire program depends on N. I am not able to figure out what to do!




program HW1_P1_a
Integer, Parameter :: N=250 !Globally used variable, hence PARAMETER
Double Precision Del_X,A(N),B(N),C(N),D(N),PA,QA,RA,PB,QB,RB
Double Precision L,M,Theta_B,Theta_L, THETA(N)
Integer I,T_B,T_L,T_INF
! "Details about Arguments used: All must be Double Precision (except N)"
! N Number of mesh points
! Del_X Mesh size
! A() Lower diagonal of tridiagonal matrix
! B() Main diagonal of tridiagonal matrix
! C() Upper diagonal of tridiagonal matrix
! D() Right side vector (do not adjust for bcs)
! PA Left b.c.(K=1): Coefficient of Theta
! QA Left b.c.(K=1): Coefficient of dTheta/Del_X
! RA Left b.c.(K=1): Right hand side
! PB Right b.c.(K=N): Coefficient of Theta
! QB Right b.c.(K=N): Coefficient of dTheta/Del_X
! RB Right b.c.(K=N): Right hand side
! L Length of Fin
! T_B Temperature at Base of Fin
! T_L Temperature at the Tip of Fin
! T_inf Temperature of surrounding air
! Theta_B Temperature excess at Fin Base
! Theta_L Temperature excess at Fin Tip
! P Perimeter
! h Heat Transfer Coeffecient
! Ac Cross Sectional Area of Fin
! K Thermal Conductivity



! Inititalising values of the variables, "Given Conditions"
T_B=200
T_L=60
T_INF=20
L=0.1
P=0.09
Ac=7.E-4
h=15
K=80



! Equation for Excess Temperature

Theta_B=T_B-T_INF
Theta_L=T_L-T_INF

! Equation for Delta X and M

Del_X=L/(N-1) !Mesh size
M=SQRT((h*P)/(K*Ac))

! Fin equation derivatives are approximated using second order accurate finite difference and multiplying with (Del_X)^2

g=M**2
f=0

! Elements of the Matrix

DO I=1,N

A(i) = 1 - (Del_X/2)*f
B(i) = -(2 + (Del_X**2)*g)
C(i) = 1 + (Del_X/2)*f
D(i) = 0

ENDDO


! Dirchlet Boundary Condition at the Base

PA=1
QA=0
RA=Theta_B

! Dirclet Boundary condition at the Tip

PB=1
QB=0
RB=Theta_L



call THOMAS(N,Del_X,A,B,C,D,PA,QA,RA,PB,QB,RB,THETA)

Write(*,*) 'Values of Theta by Numerical Solutions for N:',N


DO I=1,N

write (*,*) (I*Del_X),THETA(I)

ENDDO
End HW1_P1_a








!**********************************************************************
!
! SUBROUTINE: THOMAS
!
! DESCRIPTION: Use the Thomas algorithm to solve a system of
! linear algebraic equations where the
! coefficient matrix is tridiagonal. Boundary
! conditions can be Dirichlet, Neumann or Mixed.
!
! Left boundary condition is (X = Xmin):
!
! PA*Theta + QA*dTheta/Del_X = RA
!
! Right boundary condition is (X = Xmax):
!
! PB*Theta + QB*dTheta/Del_X = RB
!
! System of Equations:
!
! B1 C1 0 0 . . 0 = D1
! A2 B2 C2 0 . .
! 0 A3 B3 C3 . .
! . . . .
! . Ai Bi Ci = Di
! 0 . . . . An Bn = Dn
!
!
! RETURN ARGUMENTS:
! THETA() Function value
!
! VARIABLES:
!
! **********************************************************************
!
SUBROUTINE THOMAS(N,Del_X,A,B,C,D,PA,QA,RA,PB,QB,RB,THETA)

IMPLICIT DOUBLE PRECISION (A-H,O-Z)

PARAMETER (KDIM=10001)

DIMENSION A(*),B(*),C(*),D(*),THETA(*)
DIMENSION F(KDIM),DELTA(KDIM)

! -- Adjust coefficients for boundary conditions

B(1) = QA*B(1) + 2.D0*Del_X*PA*A(1)
C(1) = QA*(C(1) + A(1))
D(1) = QA*D(1) + 2.D0*Del_X*RA*A(1)

A(N) = QB*(A(N) + C(N))
B(N) = QB*B(N) - 2.D0*Del_X*PB*C(N)
D(N) = QB*D(N) - 2.D0*Del_X*RB*C(N)

! -- Forward elimination

F(1) = C(1)/B(1)
DELTA(1) = D(1)/B(1)
DO K=2,N
X1 = B(K) - A(K)*F(K-1)
X1 = 1.D0/X1
F(K) = C(K)*X1
DELTA(K) = X1*(D(K) - A(K)*DELTA(K-1))
END DO

! -- Back substitution

THETA(N) = DELTA(N)
DO K=N-1,1,-1
THETA(K) = DELTA(K) - F(K)*THETA(K+1)
END DO

RETURN
END

RE: How to initialize array dynamically to find out grid independent solution

Depends on which version of Fortran you're using. If you use from F95 onwards, you could use ALLOCATE to allocate the arrays. F90 is a bit restrictive on its use of ALLOCATE.

Look up the ALLOCATABLE declaration and ALLOCATE function. To avoid memory leaks, DEALLOCATE when you've finished.

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