Evaluation of anti-log
Evaluation of anti-log
(OP)
Greetings from England
In my kind of work, log function is very unusual.
I have found that log(number)= works fine - in that answer is correct.
y: 4.601 log(y) = 0.66285
But now I need to evaluate the anti-log...can be easily done on pocket
calculator (via inverse/shift); but how is it done in Mathcad?
By experimentation...
10^log(y) = 4.601 works, but is it correct procedure?; any neater solution?
I use Mathcad 2000.
Regards
Ed
Ed Clymer
Resinfab & Associates
England
RE: Evaluation of anti-log
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Of course I can. I can do anything. I can do absolutely anything. I'm an expert!
RE: Evaluation of anti-log
RE: Evaluation of anti-log
Thanks to IR stuff and Occupant.
IR stuff is quite correct, back to basics.
Occupant has neat solution, I will give that a try.
Help appreciated.
Regards
Ed
Ed Clymer
Resinfab & Associates
England