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Vaporization rate of liquid propane

Vaporization rate of liquid propane

Vaporization rate of liquid propane

Referring to the 11/29/00 post.
The tank pressure will probably be a maximum of 150 psi.
The smallest diameter pipe in the run will be 21/2".
The farthest length of the run will be 800ft.

RE: Vaporization rate of liquid propane

Dear VS.1

I  made a quick calculation for your case using the Panhandle formula:
              (P1-P2)^0.5394     D^2.6182
 Q = 18583 x  --------------- x ----------     where
              (Tf  L )^0.5394    G^0.4606

 Q = Gas flow in cu.ft/day [ @ 14.7 psi ,60 F ]
 P1= Initial gas pressur,psi ( 150)
 P2= Final gas pressure , psi ( 15 )
 Tf= Average gas flowing temperature ,deg R(60 F= 520 R)
 L = Pipeline length in miles ( 800/5280 = 0.1515)
 D = Pipe diameter,in ( 2.5 in)
 G = Gas gravity relative to air ( C3=1.51 )

 Substituting above values,we get

 Q = 226972  cu.ft/day  = 9457 cu.ft/hr

 Heating value of Propane is 2558 Btu/cu.ft
  Therefore you can  provide

 9457x 2558  = 24,191,006 Btu/hr (required 12,500,000)

and in the worst case you can  get (20,000,000 Btu/hr)

At the stated rate the 25,000 gals tank has to be topped every :

   25000 gal x 92290 Btu/gal( C3 heating value )
   ---------------------------------------------= 184.58 hrs
            12,500,000 Btu/hr
   or ( 8 days)

I hope this meets your requirement

Regards  Whylie
       12,500,000   Btu/hr  

RE: Vaporization rate of liquid propane


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