×
INTELLIGENT WORK FORUMS
FOR ENGINEERING PROFESSIONALS

Are you an
Engineering professional?
Join Eng-Tips Forums!
• Talk With Other Members
• Be Notified Of Responses
• Keyword Search
Favorite Forums
• Automated Signatures
• Best Of All, It's Free!

*Eng-Tips's functionality depends on members receiving e-mail. By joining you are opting in to receive e-mail.

Posting Guidelines

Promoting, selling, recruiting, coursework and thesis posting is forbidden.

Pocket Penetrometer in kg/cm^2

Pocket Penetrometer in kg/cm^2

(OP)

I read on here that people are using the direct conversion 1kg/cm^2 from a pocket penetrometer to 98.0665 kN/m^2. Whilst this is a correct conversion, if you are trying to calculate the undrained shear strength (Cu or Su)it is not correct. The pocket penetrometer test is analogous to sigma 1 in a triaxial test where sigma 3 is at or about zero. In other word the Cu value is 1/2 (sigma1-sigma3),(consider a mohr circle), which equates to half of the reading on the pocket penetrometer.

RE: Pocket Penetrometer in kg/cm^2

Divide the pocket penetrometer test result by 2 to get undrained shear strength - and don't do a whole lot of worrying about the 2# difference between kg/cm2 (tons per square foot) and kPa if you use 1 to 100.

Red Flag This Post

Please let us know here why this post is inappropriate. Reasons such as off-topic, duplicates, flames, illegal, vulgar, or students posting their homework.

Red Flag Submitted

Thank you for helping keep Eng-Tips Forums free from inappropriate posts.
The Eng-Tips staff will check this out and take appropriate action.

Close Box

Join Eng-Tips® Today!

Join your peers on the Internet's largest technical engineering professional community.
It's easy to join and it's free.

Here's Why Members Love Eng-Tips Forums:

• Talk To Other Members
• Notification Of Responses To Questions
• Favorite Forums One Click Access
• Keyword Search Of All Posts, And More...

Register now while it's still free!